Question

Дан произвольный тругольник АВС.АN и BM высоты. AN пересекает BM в точке O.Угол С =56 градусам.Найти BOA

Answer 1

Углы ONC и OMC равны по 90 град,так как BM и AN-высоты. Рассмотрим четырехугольник NOMC. сумма углов четырехугольника равна 360,найдем угол NOM. NOM=360-(уголMCN+угол ONC+ угол OMC)=360-(90+90+56)=360-236=124 град. Угол NOM и угол BOA-вертикальные и они равны между собой. Значит угол ВОА=124 град

Answer 2

Given Information

We are given a triangle ABC, where AN and BM are altitudes. AN intersects BM at point O. The angle C is 56 degrees. We need to find the measure of angle BOA.

Solution

To find the measure of angle BOA, we can use the fact that the sum of the angles in a triangle is 180 degrees.

Since AN and BM are altitudes, they are perpendicular to the opposite sides. This means that angle BAN is 90 degrees and angle BAM is also 90 degrees.

Therefore, we can find angle BOA by subtracting the sum of angles BAN and BAM from 180 degrees:

BOA = 180 degrees - (BAN + BAM)

Now, let's substitute the given information into the equation:

BOA = 180 degrees - (90 degrees + 90 degrees)

Simplifying the equation:

BOA = 180 degrees - 180 degrees

The measure of angle BOA is 0 degrees.

Please note that the given information does not provide any specific lengths or additional angles in the triangle, so we cannot determine the exact measurements of the other angles in the triangle.

I hope this helps! Let me know if you have any further questions.