Question

Решите пожалуйста! Найдите площадь равнобедренной трапеции, если её меньшее основание равно 7 см,боковая сторона -13см , высота -12см. Можно с рисунком?)...

Answer 1

S=((a+b)/2)*h=((7+17)/2)*12=12*12=144

13^2-12^2=169-144=25

✓25=5

7+(5*2)=17

Answer 2

#### Calculation of the Area of an Isosceles Trapezoid To find the area of an isosceles trapezoid, we can use the formula: **Area = (a + b) * h / 2** where: - **a** and **b** are the lengths of the parallel bases of the trapezoid, and - **h** is the height of the trapezoid. In this case, the smaller base of the trapezoid is given as 7 cm, the side length is 13 cm, and the height is 12 cm. Using the formula, we can calculate the area as follows: **Area = (7 + 13) * 12 / 2** **Area = 20 * 12 / 2** **Area = 240 / 2** **Area = 120 cm²** Therefore, the area of the given isosceles trapezoid is **120 cm²**. I apologize for not being able to provide a diagram in this text-based format. However, I hope the explanation and calculation above are clear. Let me know if you have any further questions!