Question

В четырехугольнике АBCD AB=13 BC=14 AC=16. Углы A B прямые. Найдите CD. Пожалуйста помогите. Срочно!

Answer 1

ас и вд диаганали каторые пересикаються в пункте О  и деляться на половину по уластивасти.АО=ОС=8см так как ас =16 см и во=од=7 см так как вд 14 . Р аод= ао+од+ад то ад = 25-(8+7)=10см ад . так как ад\\вс значит вс=10 см

Answer 2

Solution:

Given that in quadrilateral ABCD, AB = 13, BC = 14, AC = 16, and angles A and B are right angles, we need to find the length of CD.

To solve this problem, we can use the Pythagorean theorem and the properties of right triangles.

Let's break down the solution step by step:

1. Let's start by finding the length of AD. Since AB and AC are the legs of a right triangle, we can use the Pythagorean theorem to find AD: - AB^2 + AC^2 = AD^2 - 13^2 + 16^2 = AD^2 - 169 + 256 = AD^2 - 425 = AD^2 - AD = √425 - AD ≈ 20.62

2. Now, let's find the length of BC. Since BC is also the hypotenuse of a right triangle, we can use the Pythagorean theorem to find BC: - BC^2 = AB^2 + AC^2 - BC^2 = 13^2 + 16^2 - BC^2 = 169 + 256 - BC^2 = 425 - BC = √425 - BC ≈ 20.62

3. Since AD = BC, we can conclude that AD = BC ≈ 20.62.

4. Now, let's find the length of CD. Since AD = BC, we can conclude that CD = AC - AD: - CD = AC - AD - CD = 16 - 20.62 - CD ≈ -4.62

Based on the given information, it seems that there is an error in the problem statement. The length of CD cannot be negative. Please double-check the values provided for AB, BC, and AC.

If you have any further questions, please let me know.