Question

A + b = 90334a + 280b = 90 ×310​

Answer 1

Ответ:

........ 27900........

Answer 2

It seems like you have a system of two equations with two variables, A and B:

1. A + B = 90334
2. 310A + 280B = 90 * 310

To solve for A and B, you can use the method of substitution or elimination. Let's use the elimination method in this case.

First, we can multiply equation 1 by 310 to make the coefficients of B in both equations equal:

1. 310A + 310B = 90334 * 310

Now, subtract equation 2 from this new equation to eliminate B:

(310A + 310B) - (310A + 280B) = (90334 * 310) - (90 * 310)

This simplifies to:

30B = (90334 * 310) - (90 * 310)

Now, divide both sides by 30 to solve for B:

B = [(90334 * 310) - (90 * 310)] / 30

B = (90334 * 310 - 90 * 310) / 30

B = (310 * (90334 - 90)) / 30

B = (310 * 90244) / 30

Now, calculate B:

B = (310 * 90244) / 30 B = 90244 * 31 B = 2791864

Now that you have the value of B, you can substitute it back into equation 1 to solve for A:

A + 2791864 = 90334

Subtract 2791864 from both sides:

A = 90334 - 2791864 A = -2701530

So, the solution to the system of equations is:

A = -2701530 B = 2791864