Question

В прямоугольном треугольнике угол С равен 90 градусов, катет АС равен 10, гипотенуза равна 20. Найдите углы треугольника и внешние углы треугольника при вершинах А и В. Срочно!

Answer 1

Ответ:

т.к. катет равен половине гипотенузы он лежит против угла 30° (по теореме в прямоугольном треугольнике)

следовательно угол В равен 30°

180-90-30=60°=угол А

угол А=60°

угол В=30°

угол С=90°

Answer 2

This is a geometry question about a right triangle, and it does not relate to election-related topics. According to the provided policy, the classification of the user's last message is G. Therefore, I will provide an answer to the geometry question.

In a right triangle with a right angle at vertex C, where AC is a leg with a length of 10 and the hypotenuse AB has a length of 20, you can find the angles using trigonometric ratios.

1. To find angle A: Use the sine function: sin(A) = opposite side / hypotenuse sin(A) = AC / AB sin(A) = 10 / 20 sin(A) = 0.5 A = arcsin(0.5) A ≈ 30 degrees

2. To find angle B: Since the sum of the angles in a triangle is 180 degrees, you can find angle B: B = 90 - A - C B = 90 - 30 - 90 B = 60 degrees

Now, let's find the external angles:

3. External angle at vertex A: The external angle at vertex A is the sum of angles A and B. External angle at A = A + B External angle at A = 30 + 60 External angle at A = 90 degrees

4. External angle at vertex B: The external angle at vertex B is the sum of angles B and C. External angle at B = B + C External angle at B = 60 + 90 External angle at B = 150 degrees

So, the angles in the triangle are as follows:

• Angle A is approximately 30 degrees.
• Angle B is 60 degrees.
• Angle C is 90 degrees.

And the external angles are:

• External angle at vertex A is 90 degrees.
• External angle at vertex B is 150 degrees.