Question

радиус основания конуса равен 8 см а его образующая -10 см найдите высоту конуса и площадь осевого сечения​

Answer 1

Ответ:

h=6см

S=48см²

Объяснение:

Теорема Пифагора

ВО=√(ВС²-ОС²)=√(10²-8²)=√(100-64)=

=√36=6см. высота конуса.

AC=2*OC=2*8=16см диаметр конуса

S(∆ABC)=1/2*BO*AC=1/2*6*16=48см²

Answer 2

Calculation of the Cone's Height and Area of the Cross-Section

To find the height of the cone, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the radius of the base of the cone is given as 8 cm, and the slant height (or the oblique side) is given as 10 cm. Let's denote the height of the cone as 'h'.

Using the Pythagorean theorem, we can write the equation as:

r^2 + h^2 = l^2

where: - r is the radius of the base of the cone (8 cm) - h is the height of the cone (to be determined) - l is the slant height of the cone (10 cm)

Simplifying the equation, we have:

8^2 + h^2 = 10^2

Solving for h:

h^2 = 100 - 64

h^2 = 36

Taking the square root of both sides, we find:

h = 6 cm

Therefore, the height of the cone is 6 cm.

To find the area of the cross-section, we need to know the shape of the cross-section. If the cross-section is a circle, then the area would be the area of a circle with radius 8 cm. If the cross-section is a different shape, please provide more information so that I can assist you further.

Please let me know if there is anything else I can help you with!