Question

Кут при вершині при вершині рівнобедриного трикутника дорівнює 70° знайдіть кути при основі​

Answer 1

Ответ:

По 55°

Объяснение:

∠1+∠2+∠3=180°

∠1+∠2+70°=180°
∠1+∠2=110°

∠1=∠2 - за властивістю рівнобедренного трикутника;

∠1=∠2=110°/2=55°

Answer 2

Finding the Angles at the Base of an Isosceles Triangle

To find the angles at the base of an isosceles triangle when the angle at the vertex is given, we can use the property that in an isosceles triangle, the base angles are equal. Let's denote the angles at the base as x each.

Calculation

Given that the angle at the vertex of the isosceles triangle is 70°, we can use the property of isosceles triangles to find the angles at the base.

Since the triangle is isosceles, the angles at the base are equal. Therefore, both angles at the base are equal to x.

We can use the fact that the sum of the angles in a triangle is 180° to find the value of x.

So, we have: - Angle at the vertex = 70° - Angle at the base = x

Using the fact that the sum of the angles in a triangle is 180°, we can set up the equation: 70° + x + x = 180°

Solving for x: 70° + 2x = 180° 2x = 180° - 70° 2x = 110° x = 110° / 2 x = 55°

Answer

Therefore, the angles at the base of the isosceles triangle are both 55° each.