Question

Знайти кути рівнобедренного трикутника якщо кут при його вершині дорівнює 80 градусів

Answer 1

180 -80 =100
<1 = <2
100 : 2= 50
<1 =50
<2 =50

Answer 2

Finding the angles of an isosceles triangle

To find the angles of an isosceles triangle when one angle at its vertex is 80 degrees, we can use the properties of isosceles triangles.

An isosceles triangle is a triangle that has two sides of equal length. In an isosceles triangle, the angles opposite the equal sides are also equal.

Let's denote the angles of the isosceles triangle as follows: - The angle at the vertex: A (which is given as 80 degrees) - The angles opposite the equal sides: B and C

Since the triangle is isosceles, angles B and C are equal.

To find the values of angles B and C, we can use the fact that the sum of the angles in a triangle is always 180 degrees.

The sum of the angles in the triangle can be expressed as: A + B + C = 180 degrees

Since we know that angle A is 80 degrees, we can substitute this value into the equation: 80 + B + C = 180 degrees

To find the values of angles B and C, we can solve this equation.

Let's do the math:

80 + B + C = 180 B + C = 180 - 80 B + C = 100

Since angles B and C are equal, we can divide the sum by 2 to find the value of each angle: B = C = 100 / 2 B = C = 50

Therefore, the angles of the isosceles triangle are: Angle A = 80 degrees Angle B = 50 degrees Angle C = 50 degrees

So, the angles of the isosceles triangle with a vertex angle of 80 degrees are 80 degrees, 50 degrees, and 50 degrees.

I hope this helps! Let me know if you have any further questions.