Question

Расставить коэфиценты и указать к какому типу: 1)Al+Fe2O3→Fe+Al2O3 2)F^1eCl2 +Cl2 →FeM3 3)CrCl3+NaOH→Cr(OH)-3↓+HaCl. 4)CuO+HNO3→CuCl2+H2O. 5)CuO+HNO3→Cu(NO3)2+H2O. 6)N2O3+H2O→HNO3. 7)KCLO3→KCL+KCLO4. 8)NaNO3→NaNO2+O2. 9)H2S+CL2→S+HCL

Answer 1

2Al + Fe2O3 = Al2O3 + 2Fe  ( замещение)

2FeCl2 + Cl2 = 2FeCl3          (соединение)

CrCl3 + 3NaOH = Cr(OH)3 + 3NaCl  (обмен)

CuO + 2HCl = CuCl2 + H2O (обмен)

CuO +2 HNO3 = Cu(NO3)2 + H2O (обмен)

N2O5 + H2O =2 HNO3  (соединение)

2KClO3 = KCl + KClO4 +O2 (разложение)

2NaNO3 =2 NaNO2 + O2 (разложение)

H2S + Cl2 = S +2 HCl (замещение)

Answer 2

1) Al Fe2O3 → Fe Al2O3

The given equation represents a redox reaction between aluminum (Al) and iron(III) oxide (Fe2O3). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

2 Al + Fe2O3 → 2 Fe + Al2O3 [[1]]

This reaction is an example of a single replacement reaction, where aluminum displaces iron from iron(III) oxide to form aluminum oxide and iron.

2) F^1eCl2 + Cl2 → FeCl3

The given equation represents a redox reaction between iron(II) chloride (FeCl2) and chlorine gas (Cl2). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

2 FeCl2 + Cl2 → 2 FeCl3 [[2]]

This reaction is an example of a combination reaction, where iron(II) chloride reacts with chlorine gas to form iron(III) chloride.

3) CrCl3 + NaOH → Cr(OH)3↓ + NaCl

The given equation represents a precipitation reaction between chromium(III) chloride (CrCl3) and sodium hydroxide (NaOH). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

CrCl3 + 3 NaOH → Cr(OH)3↓ + 3 NaCl [[3]]

In this reaction, chromium(III) chloride reacts with sodium hydroxide to form chromium(III) hydroxide, which is insoluble and precipitates out of the solution, and sodium chloride.

4) CuO + HNO3 → Cu(NO3)2 + H2O

The given equation represents a redox reaction between copper(II) oxide (CuO) and nitric acid (HNO3). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

3 CuO + 6 HNO3 → 3 Cu(NO3)2 + 3 H2O [[4]]

In this reaction, copper(II) oxide reacts with nitric acid to form copper(II) nitrate and water.

5) CuO + HNO3 → Cu(NO3)2 + H2O

The given equation is the same as the previous one. Here's the balanced equation:

3 CuO + 8 HNO3 → 3 Cu(NO3)2 + 4 H2O [[5]]

This balanced equation shows that for every 3 moles of copper(II) oxide, 8 moles of nitric acid are required to produce 3 moles of copper(II) nitrate and 4 moles of water.

6) N2O3 + H2O → 2 HNO3

The given equation represents a reaction between dinitrogen trioxide (N2O3) and water (H2O). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

N2O3 + H2O → 2 HNO3 [[6]]

In this reaction, dinitrogen trioxide reacts with water to form nitric acid.

7) KCLO3 → KCl + KCLO4

The given equation represents a decomposition reaction of potassium chlorate (KClO3). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

2 KClO3 → 2 KCl + 3 O2 [[7]]

In this reaction, potassium chlorate decomposes to form potassium chloride and oxygen gas.

8) NaNO3 → NaNO2 + O2

The given equation represents a decomposition reaction of sodium nitrate (NaNO3). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

2 NaNO3 → 2 NaNO2 + O2 [[8]]

In this reaction, sodium nitrate decomposes to form sodium nitrite and oxygen gas.

9) H2S + Cl2 → S + 2 HCl

The given equation represents a redox reaction between hydrogen sulfide (H2S) and chlorine gas (Cl2). The coefficients need to be determined to balance the equation.

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

H2S + Cl2 → S + 2 HCl [[9]]

In this reaction, hydrogen sulfide reacts with chlorine gas to form sulfur and hydrogen chloride.