Question

вычислите массу спирта,полученную при гидратации 46г этилена, если практический выход спирта составляет 60%

Answer 1

CH2=CH2+H2O=C2H5OH (H2SO4,t над равно)

1) n(C2H4)= 46/28= 1.64 моль

2)n(C2H5OH)= 1.64 моль

3) m(C2H5OH)теор = 1.64 * 46 = 75.44 г

4) m(C2H5OH) практ = 75.44/100 * 60 = 45.264 г

Answer 2

Calculation of the Mass of Alcohol Obtained from the Hydration of Ethylene

To calculate the mass of alcohol obtained from the hydration of 46 grams of ethylene, we need to consider the practical yield of alcohol, which is given as 60%.

The equation for the hydration of ethylene is as follows:

C2H4 + H2O → C2H5OH

According to the equation, one mole of ethylene (C2H4) reacts with one mole of water (H2O) to produce one mole of ethanol (C2H5OH).

To calculate the mass of alcohol obtained, we can follow these steps:

Step 1: Calculate the number of moles of ethylene: The molar mass of ethylene (C2H4) is 28.05 g/mol. Therefore, the number of moles of ethylene can be calculated as follows:

Number of moles of ethylene = Mass of ethylene / Molar mass of ethylene

Plugging in the values, we get:

Number of moles of ethylene = 46 g / 28.05 g/mol

Step 2: Calculate the number of moles of alcohol: Since the equation shows a 1:1 ratio between ethylene and alcohol, the number of moles of alcohol will be the same as the number of moles of ethylene.

Step 3: Calculate the mass of alcohol obtained: The molar mass of ethanol (C2H5OH) is 46.07 g/mol. Therefore, the mass of alcohol obtained can be calculated as follows:

Mass of alcohol obtained = Number of moles of alcohol × Molar mass of ethanol

Plugging in the values, we get:

Mass of alcohol obtained = Number of moles of alcohol × 46.07 g/mol

However, we need to take into account the practical yield of alcohol, which is given as 60%. This means that only 60% of the calculated mass of alcohol is actually obtained.

Therefore, the final calculation for the mass of alcohol obtained is:

Mass of alcohol obtained = (Number of moles of alcohol × 46.07 g/mol) × 0.60

Now, let's calculate the mass of alcohol obtained using the given information.

Using the equation above, we can calculate the number of moles of ethylene:

Number of moles of ethylene = 46 g / 28.05 g/mol = 1.64 mol

Since the equation shows a 1:1 ratio between ethylene and alcohol, the number of moles of alcohol will also be 1.64 mol.

Now, let's calculate the mass of alcohol obtained:

Mass of alcohol obtained = (1.64 mol × 46.07 g/mol) × 0.60 = 57.29 g

Therefore, the mass of alcohol obtained from the hydration of 46 grams of ethylene, considering a practical yield of 60%, is approximately 57.29 grams.

Please note that the calculation assumes ideal conditions and does not take into account any other factors that may affect the yield of the reaction.