Question

SO2+H6TeO6->Te+3H2SO4

Answer 1

3SO2+H6TeO6->Te+3H2SO4

Answer 2

The given chemical equation is:

SO2 + H6TeO6 -> Te + 3H2SO4

This equation represents the reaction between sulfur dioxide (SO2) and hexahydroxotellurate(IV) acid (H6TeO6), resulting in the formation of tellurium (Te) and sulfuric acid (H2SO4).

Here's a breakdown of the reaction:

1. Sulfur dioxide (SO2) is a colorless gas with a pungent odor. It is produced from the combustion of sulfur-containing fuels, such as coal and oil. SO2 is also released during volcanic eruptions and certain industrial processes. It is a toxic gas and a major contributor to air pollution.

2. Hexahydroxotellurate(IV) acid (H6TeO6) is an inorganic compound containing the tellurium element. It is a strong acid and can be considered as a derivative of telluric acid (H6TeO6). The compound is not commonly encountered and is mainly used in research and laboratory settings.

3. The reaction between SO2 and H6TeO6 results in the formation of tellurium (Te) and sulfuric acid (H2SO4). Tellurium is a brittle, silver-white metalloid element that is often found in association with gold and other metals. It has various industrial applications, including its use in the production of alloys, semiconductors, and solar panels.

4. Sulfuric acid (H2SO4) is a strong acid commonly used in various industrial processes. It is a highly corrosive liquid and has numerous applications, including its use in the production of fertilizers, dyes, detergents, and batteries.

In summary, the reaction between sulfur dioxide (SO2) and hexahydroxotellurate(IV) acid (H6TeO6) produces tellurium (Te) and sulfuric acid (H2SO4).