Вопрос задан 20.02.2019 в 14:47. Предмет Химия. Спрашивает Радзієвська Світлана.

Расставьте коэффициенты с помощью электронного баланса: 1. Cu + HNO3(разб.) = =Cu(NO3)2 + NO + H2O

2. H2SO4(конц.) + Mg = MgSO4 + H2S +H2O 3. Fe +HNO3(разб.) = Fe(NO3)3 + NH4NO3 4. H2SO4(конц.) + Cu = CuSO4 + SO2 + H2O
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Отвечает Semchuk Lilia.
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

1. Cu + HNO3(разб.) = Cu(NO3)2 + NO + H2O

To balance this equation using an electronic balance, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's start by balancing the copper (Cu) atoms:

On the left side, we have 1 Cu atom, and on the right side, we have 1 Cu atom in Cu(NO3)2. So, the copper atoms are already balanced.

Next, let's balance the nitrogen (N) atoms:

On the left side, we have 1 N atom in HNO3, and on the right side, we have 2 N atoms in Cu(NO3)2 and 1 N atom in NO. To balance the nitrogen atoms, we need to multiply HNO3 by 2:

2 Cu + 4 HNO3(разб.) = 2 Cu(NO3)2 + NO + H2O

Now, let's balance the oxygen (O) atoms:

On the left side, we have 12 O atoms in 4 HNO3, and on the right side, we have 14 O atoms in 2 Cu(NO3)2 and 1 O atom in H2O. To balance the oxygen atoms, we need to add a coefficient of 6 in front of H2O:

2 Cu + 4 HNO3(разб.) = 2 Cu(NO3)2 + NO + 6 H2O

Finally, let's balance the hydrogen (H) atoms:

On the left side, we have 16 H atoms in 4 HNO3, and on the right side, we have 12 H atoms in 6 H2O. To balance the hydrogen atoms, we need to add a coefficient of 8 in front of HNO3:

2 Cu + 8 HNO3(разб.) = 2 Cu(NO3)2 + NO + 6 H2O

Therefore, the balanced equation is:

2 Cu + 8 HNO3(разб.) = 2 Cu(NO3)2 + NO + 6 H2O [[1]]

2. H2SO4(конц.) + Mg = MgSO4 + H2S + H2O

Let's balance this equation using an electronic balance. We'll start by balancing the sulfur (S) atoms:

On the left side, we have 1 S atom in H2SO4, and on the right side, we have 1 S atom in MgSO4 and 1 S atom in H2S. So, the sulfur atoms are already balanced.

Next, let's balance the hydrogen (H) atoms:

On the left side, we have 4 H atoms in H2SO4, and on the right side, we have 4 H atoms in H2S and 2 H atoms in H2O. So, the hydrogen atoms are already balanced.

Finally, let's balance the magnesium (Mg) atoms:

On the left side, we have 1 Mg atom, and on the right side, we have 1 Mg atom in MgSO4. So, the magnesium atoms are already balanced.

Therefore, the balanced equation is:

H2SO4(конц.) + Mg = MgSO4 + H2S + H2O [[2]]

3. Fe + HNO3(разб.) = Fe(NO3)3 + NH4NO3

Let's balance this equation using an electronic balance. We'll start by balancing the iron (Fe) atoms:

On the left side, we have 1 Fe atom, and on the right side, we have 1 Fe atom in Fe(NO3)3. So, the iron atoms are already balanced.

Next, let's balance the nitrogen (N) atoms:

On the left side, we have 1 N atom in HNO3, and on the right side, we have 3 N atoms in Fe(NO3)3 and 1 N atom in NH4NO3. To balance the nitrogen atoms, we need to multiply HNO3 by 3:

3 Fe + 3 HNO3(разб.) = Fe(NO3)3 + NH4NO3

Therefore, the balanced equation is:

3 Fe + 3 HNO3(разб.) = Fe(NO3)3 + NH4NO3 [[3]]

4. H2SO4(конц.) + Cu = CuSO4 + SO2 + H2O

Let's balance this equation using an electronic balance. We'll start by balancing the sulfur (S) atoms:

On the left side, we have 1 S atom in H2SO4, and on the right side, we have 1 S atom in CuSO4 and 1 S atom in SO2. So, the sulfur atoms are already balanced.

Next, let's balance the hydrogen (H) atoms:

On the left side, we have 4 H atoms in H2SO4, and on the right side, we have 2 H atoms in H2O. To balance the hydrogen atoms, we need to add a coefficient of 4 in front of H2O:

H2SO4(конц.) + Cu = CuSO4 + SO2 + 4 H2O

Finally, let's balance the copper (Cu) atoms:

On the left side, we have 1 Cu atom, and on the right side, we have 1 Cu atom in CuSO4. So, the copper atoms are already balanced.

Therefore, the balanced equation is:

H2SO4(конц.) + Cu = CuSO4 + SO2 + 4 H2O [[4]]

Please note that the coefficients provided above are based on the assumption that the reaction is balanced in terms of atoms. The coefficients may differ if the reaction is balanced in terms of moles or other units.

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