Question

ПОМОГИТЕ ПОЖАЛУЙСТА Расставьте коэффициенты методом электронного баланса в уравнениях: H2S+Na=NA2S+H2 NH3+NO=N2+H2O H2S+O2=SO2+H2O

Answer 1

1)H2S+2Na=Na2S +H2
2)4NH3+6NO=5N2+6H2O
3)4H2S+6O2=4SO2+4H2O

Answer 2

H2S+2Na=Na2S+H2...........

Answer 3

Balancing Chemical Equations using the Method of Electron Balance

To balance the given chemical equations using the method of electron balance, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We will start by balancing the elements that appear in the fewest number of compounds.

Let's balance the given equations step by step:

1. H2S + Na = Na2S + H2

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.

On the left side, we have: - 2 hydrogen (H) atoms - 1 sulfur (S) atom - 1 sodium (Na) atom

On the right side, we have: - 2 sodium (Na) atoms - 1 sulfur (S) atom - 2 hydrogen (H) atoms

To balance the hydrogen (H) atoms, we can place a coefficient of 2 in front of H2 on the left side: H2S + Na = Na2S + 2H2

Now, the equation becomes: 1 hydrogen (H) atom on the left side and 4 hydrogen (H) atoms on the right side.

To balance the sodium (Na) atoms, we can place a coefficient of 2 in front of Na on the left side: 2H2S + 2Na = Na2S + 2H2

Now, the equation becomes: 2 sodium (Na) atoms on both sides.

The balanced equation is: 2H2S + 2Na = Na2S + 2H2

2. NH3 + NO = N2 + H2O

On the left side, we have: - 3 hydrogen (H) atoms - 1 nitrogen (N) atom - 1 oxygen (O) atom

On the right side, we have: - 2 hydrogen (H) atoms - 2 nitrogen (N) atoms - 1 oxygen (O) atom

To balance the hydrogen (H) atoms, we can place a coefficient of 4 in front of NH3 on the left side: 4NH3 + NO = N2 + H2O

Now, the equation becomes: 12 hydrogen (H) atoms on the left side and 4 hydrogen (H) atoms on the right side.

To balance the nitrogen (N) atoms, we can place a coefficient of 2 in front of N2 on the right side: 4NH3 + NO = 2N2 + H2O

Now, the equation becomes: 2 nitrogen (N) atoms on both sides.

The balanced equation is: 4NH3 + NO = 2N2 + H2O

3. H2S + O2 = SO2 + H2O

On the left side, we have: - 2 hydrogen (H) atoms - 1 sulfur (S) atom - 2 oxygen (O) atoms

On the right side, we have: - 1 sulfur (S) atom - 2 oxygen (O) atoms - 2 hydrogen (H) atoms

To balance the hydrogen (H) atoms, we can place a coefficient of 2 in front of H2O on the right side: H2S + O2 = SO2 + 2H2O

Now, the equation becomes: 4 hydrogen (H) atoms on both sides.

The balanced equation is: H2S + O2 = SO2 + 2H2O

Therefore, the balanced equations using the method of electron balance are: 1. 2H2S + 2Na = Na2S + 2H2 2. 4NH3 + NO = 2N2 + H2O 3. H2S + O2 = SO2 + 2H2O

Please let me know if you need any further assistance!