Question

Осуществить превращения.назвать реагенты и продукты реакции. Пропан+cl2+2na+alcl3--->co2

Answer 1

1)CH3-CH2-CH3+Cl2---->CH2Cl-CH2-CH3+HCl
2)2CH2Cl-CH2-CH3+2Na----->2NaCl+C6H14
3)C6H14----AlCl3----->C6H12+H2
4)C6H12+9O2=6CO2+6H2O

Answer 2

Chemical Reaction and Products

The given chemical reaction involves the transformation of propane (C3H8) in the presence of chlorine (Cl2), sodium (2Na), and aluminum chloride (AlCl3) to produce carbon dioxide (CO2).

The balanced chemical equation for the reaction is as follows: C3H8 + Cl2 + 2Na + AlCl3 → CO2

The reagents and products involved in this reaction are: - Reagents: - Propane (C3H8) - Chlorine (Cl2) - Sodium (2Na) - Aluminum chloride (AlCl3) - Products: - Carbon dioxide (CO2)

This reaction is a substitution reaction where the chlorine atoms replace the hydrogen atoms in the propane molecule, resulting in the formation of carbon dioxide as one of the products.

Explanation of the Reaction

The reaction proceeds as follows: 1. Chlorine (Cl2) reacts with aluminum chloride (AlCl3) to form a complex that acts as a catalyst in the reaction. 2. The chlorine atoms are then substituted for the hydrogen atoms in the propane molecule, resulting in the formation of carbon dioxide (CO2) as one of the products.

This reaction is an example of a halogenation reaction, where a halogen (in this case, chlorine) replaces a hydrogen atom in an organic compound.

I hope this explanation helps! If you have further questions or need more details, feel free to ask.