
ОБЧИСЛИТИ КІЛЬКІСТЬ МОЛЕКУЛ ТА АТОМІВ, ЩО МІСТИТЬСЯ В 89,6 Л КИСНЮ ПРИ НОРМАЛЬНИХ УМОВАХ.


Ответы на вопрос

Ответ:
Дано:
V(O2)=89,6 л N= NA∙V/22,4
Nмол.(О2)=6,02 моль-1·89,6л/22,4 л/моль=24,08·1023
Nмол.-?, Nатомів-? Nатомів(О)=2· Nмол.(О2)=2·24,08·1023=48,16·1023
Відповідь: 24,08·1023 молекул; 48,16·1023 атомів.
Объяснение:



Calculation of the Number of Molecules and Atoms in 89.6 L of Oxygen at Normal Conditions
To calculate the number of molecules and atoms in 89.6 L of oxygen at normal conditions, we need to use the ideal gas law and Avogadro's number.
Avogadro's number is a fundamental constant in chemistry and is equal to approximately 6.022 x 10^23. It represents the number of atoms, molecules, or ions in one mole of a substance.
The ideal gas law equation is given by:
PV = nRT
Where: - P is the pressure of the gas (at normal conditions, it is approximately 1 atmosphere) - V is the volume of the gas (given as 89.6 L) - n is the number of moles of the gas (what we want to calculate) - R is the ideal gas constant (approximately 0.0821 L·atm/(mol·K)) - T is the temperature of the gas (at normal conditions, it is approximately 273.15 K)
To calculate the number of moles, we rearrange the ideal gas law equation as follows:
n = PV / RT
Substituting the given values:
n = (1 atm) * (89.6 L) / (0.0821 L·atm/(mol·K) * 273.15 K)
Simplifying the equation:
n = 1.036 mol
Now that we have the number of moles, we can calculate the number of molecules and atoms using Avogadro's number.
Since 1 mole of any substance contains approximately 6.022 x 10^23 particles, the number of molecules and atoms in 1.036 moles of oxygen is:
Number of molecules = (1.036 mol) * (6.022 x 10^23 molecules/mol)
Number of atoms = (1.036 mol) * (6.022 x 10^23 atoms/mol)
Calculating the values:
Number of molecules = 6.235 x 10^23 molecules
Number of atoms = 6.235 x 10^23 atoms
Therefore, in 89.6 L of oxygen at normal conditions, there are approximately 6.235 x 10^23 molecules and 6.235 x 10^23 atoms.


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