При взаимодействии магния массой 3,8г с раствором серной кислоты получили соль массой 7,9г.
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Calculation of Reaction Yield
To determine the reaction yield, we need to compare the mass of the product obtained to the theoretical yield. The theoretical yield is the maximum amount of product that can be obtained based on the stoichiometry of the reaction.
In this case, we have magnesium (Mg) reacting with sulfuric acid (H2SO4) to form a salt. The balanced chemical equation for this reaction is:
Mg + H2SO4 → MgSO4 + H2
According to the problem statement, the mass of magnesium used is 3.8 grams, and the mass of the salt obtained is 7.9 grams.
To calculate the theoretical yield, we need to determine the molar mass of magnesium sulfate (MgSO4). The molar mass of magnesium (Mg) is 24.31 g/mol, sulfur (S) is 32.07 g/mol, and oxygen (O) is 16.00 g/mol.
The molar mass of magnesium sulfate (MgSO4) can be calculated as follows:
Mg: 1 × 24.31 g/mol = 24.31 g/mol S: 1 × 32.07 g/mol = 32.07 g/mol O: 4 × 16.00 g/mol = 64.00 g/mol
Adding up the molar masses gives us:
MgSO4: 24.31 g/mol + 32.07 g/mol + 64.00 g/mol = 120.38 g/mol
Now we can calculate the theoretical yield using the following formula:
Theoretical Yield = (Mass of Magnesium × Molar Mass of MgSO4) / Molar Mass of Mg
Substituting the given values:
Theoretical Yield = (3.8 g × 120.38 g/mol) / 24.31 g/mol
Calculating this expression gives us the theoretical yield of the reaction.
Calculation:
Theoretical Yield = (3.8 g × 120.38 g/mol) / 24.31 g/mol
Theoretical Yield = 18.8 g
Now we can calculate the reaction yield as a percentage using the following formula:
Reaction Yield (%) = (Actual Yield / Theoretical Yield) × 100
Substituting the given values:
Reaction Yield (%) = (7.9 g / 18.8 g) × 100
Calculating this expression gives us the reaction yield as a percentage.
Calculation:
Reaction Yield (%) = (7.9 g / 18.8 g) × 100
Reaction Yield (%) = 41.96%
Therefore, the yield of the reaction is approximately 41.96%.
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