Question

Срочно!!!Даю 50баллов! какой объем этилена получили в результате дегидратации 207 грамм этанола, если относительный выход этилена 98%? задачу надо розписать

Answer 1

Прости но 10-11 класс и слово "Разписать" это трэш. Правильно "Расписать". Это же элементарна Ватсон!

Answer 2

Calculation of Ethylene Volume Obtained from Dehydration of Ethanol

To calculate the volume of ethylene obtained from the dehydration of 207 grams of ethanol with a relative yield of 98%, we can use the following steps:

1. Molar Mass of Ethanol (C2H5OH): - The molar mass of ethanol (C2H5OH) can be calculated by adding the atomic masses of its constituent elements. - The molar mass of ethanol is approximately 46.07 grams per mole.

2. Moles of Ethanol (C2H5OH): - To find the moles of ethanol, we can use the given mass of ethanol and its molar mass. - Moles of ethanol = Mass of ethanol / Molar mass of ethanol - Moles of ethanol = 207 grams / 46.07 grams per mole - Moles of ethanol ≈ 4.49 moles

3. Moles of Ethylene (C2H4) Obtained: - The dehydration of ethanol produces ethylene (C2H4) and water (H2O). - The balanced chemical equation for the dehydration of ethanol is: C2H5OH → C2H4 + H2O - From the equation, it is clear that 1 mole of ethanol produces 1 mole of ethylene. - Therefore, the moles of ethylene obtained will be the same as the moles of ethanol, which is approximately 4.49 moles.

4. Volume of Ethylene at Standard Conditions: - At standard temperature and pressure (STP), 1 mole of any gas occupies approximately 22.4 liters. - Therefore, the volume of ethylene obtained can be calculated as: - Volume of ethylene = Moles of ethylene * Molar volume at STP - Volume of ethylene = 4.49 moles * 22.4 liters/mole - Volume of ethylene ≈ 100.58 liters

Conclusion:

The volume of ethylene obtained from the dehydration of 207 grams of ethanol, with a relative yield of 98%, is approximately 100.58 liters.