Question

(СРОЧНО ПОМОГИТЕ)Допишіть схеми реакцій : a) КОН + N2O5 → б) Ва(ОН)2 + K2SO4 →​

Answer 1

a) 2KOH + N2O5 → 2KNO3 + H2O

b) Ba(OH)2 + K2SO4 → BaSO4↓ + 2KOH

лучший ответ пж

Answer 2

a) КОН + N2O5 → ?

The reaction between potassium hydroxide (KOH) and dinitrogen pentoxide (N2O5) can be represented by the following balanced chemical equation:

2 KOH + N2O5 → 2 KNO3 + H2O

In this reaction, potassium hydroxide reacts with dinitrogen pentoxide to produce potassium nitrate and water. The balanced equation shows that 2 moles of KOH react with 1 mole of N2O5 to produce 2 moles of KNO3 and 1 mole of H2O.

b) Ва(ОН)2 + K2SO4 → ?

The reaction between barium hydroxide (Ba(OH)2) and potassium sulfate (K2SO4) can be represented by the following balanced chemical equation:

Ba(OH)2 + K2SO4 → BaSO4 + 2 KOH

In this reaction, barium hydroxide reacts with potassium sulfate to produce barium sulfate and potassium hydroxide. The balanced equation shows that 1 mole of Ba(OH)2 reacts with 1 mole of K2SO4 to produce 1 mole of BaSO4 and 2 moles of KOH