Question

Срочноооооо!!!!!! Определите, какая масса соли образуется при сжигании 22,4 г железа в хлоре объемом 22,4 л.

Answer 1

Ответ:

Уравнение реакции сгорания железа в хлоре:

Fe + 2Cl2 → FeCl4

Молярная масса Fe = 55,85 г/моль

Молярная масса Cl2 = 70,90 г/моль

Мольный объем газов при стандартных условиях равен 22,4 л/моль.

Переведем массу железа в моль:

n(Fe) = m/M(Fe) = 22,4 г / 55,85 г/моль ≈ 0,40 моль

Так как соотношение между Fe и Cl2 в реакции 1:2, то мольное количество Cl2, участвующее в реакции, будет равно 0,80 моль.

Теперь можно посчитать массу FeCl4:

m(FeCl4) = n(FeCl4) * M(FeCl4) = n(Cl2) * M(FeCl4) = 0,80 моль * (55,85 г/моль + 4*35,45 г/моль) ≈ 201 г

Таким образом, при сжигании 22,4 г железа в хлоре образуется примерно 201 г FeCl4.

Answer 2

Calculation of the Mass of Salt Formed

To determine the mass of salt formed when 22.4 grams of iron is burned in 22.4 liters of chlorine gas, we need to consider the balanced chemical equation for the reaction between iron and chlorine.

The balanced chemical equation for the reaction is:

2 Fe + 3 Cl2 -> 2 FeCl3

From the balanced equation, we can see that 2 moles of iron react with 3 moles of chlorine gas to produce 2 moles of iron(III) chloride.

To calculate the mass of salt formed, we need to convert the given mass of iron to moles using its molar mass and then use the mole ratio from the balanced equation to determine the moles of iron(III) chloride formed. Finally, we can convert the moles of iron(III) chloride to grams using its molar mass.

Let's calculate the mass of salt formed step by step:

1. Calculate the moles of iron: - Molar mass of iron (Fe) = 55.845 g/mol - Moles of iron = mass of iron / molar mass of iron - Moles of iron = 22.4 g / 55.845 g/mol

2. Use the mole ratio from the balanced equation to determine the moles of iron(III) chloride formed: - Moles of iron(III) chloride = (moles of iron) x (2 moles of iron(III) chloride / 2 moles of iron)

3. Calculate the mass of iron(III) chloride formed: - Molar mass of iron(III) chloride (FeCl3) = 162.204 g/mol - Mass of iron(III) chloride = moles of iron(III) chloride x molar mass of iron(III) chloride

Let's calculate the values:

1. Moles of iron: - Moles of iron = 22.4 g / 55.845 g/mol = 0.401 moles

2. Moles of iron(III) chloride: - Moles of iron(III) chloride = 0.401 moles x (2 moles of iron(III) chloride / 2 moles of iron) = 0.401 moles

3. Mass of iron(III) chloride: - Mass of iron(III) chloride = 0.401 moles x 162.204 g/mol = 65.115 g

Therefore, the mass of salt formed when 22.4 grams of iron is burned in 22.4 liters of chlorine gas is approximately 65.115 grams