Question

1. Допишіть рівняння реакцій, розставте коефіцієнти: LiOH + SO3 = Pb(OH)2 t→ Ba(OH)2 + H3PO4 = KOH + P2O5 = NaOH + AlCl3 = Ba(OH)2 + CuSO4 = Al(OH)3 t→ LiOH + ZnCl2 = Ca(OH)2 + CO2 = Ca(OH)2 + HNO3 = LiOH + H2SiO3 = NaOH + H2S =

Answer 1

Ответ:

Объяснение:

2LiOH + SO3 = Li2SO4 + H2O

Pb(OH)2 = PbO + H2O

3Ba(OH)2 + 2H3PO4 = Ba3(PO4)2 + 6H2O

6KOH + P2O5 = 2K3PO4  + 3H2O

3NaOH + AlCl3 = Al(OH)3 + NaCl

Ba(OH)2 + CuSO4 = BaSO4 + Cu(OH)2

2Al(OH)3 = Al2O3 + 3H2O

2LiOH + ZnCl2 = Zn(OH)2 + 2LiCl

Ca(OH)2 + CO2 = CaCO3 + H2O

Ca(OH)2 + H2SiO3 = CaSiO3 + 2H2O

2NaOH + H2S = Na2S + 2H2O

Answer 2

Balancing Chemical Equations:

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation one by one:

1. LiOH + SO3 = Pb(OH)2 + t To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's start by balancing the elements one by one: - Balance Li: There is 1 Li atom on the left and 0 Li atoms on the right. We can balance it by placing a coefficient of 2 in front of LiOH on the left side. - Balanced equation: 2LiOH + SO3 = Pb(OH)2 + t

2. Ba(OH)2 + H3PO4 = KOH + P2O5 + NaOH - Balance Ba: There is 1 Ba atom on the left and 0 Ba atoms on the right. We can balance it by placing a coefficient of 3 in front of Ba(OH)2 on the right side. - Balance H: There are 6 H atoms on the left and 4 H atoms on the right. We can balance it by placing a coefficient of 4 in front of H3PO4 on the left side. - Balanced equation: 3Ba(OH)2 + 4H3PO4 = KOH + P2O5 + NaOH

3. AlCl3 + Ba(OH)2 = CuSO4 + Al(OH)3 + t - Balance Al: There is 1 Al atom on the left and 1 Al atom on the right. It is already balanced. - Balance Cl: There are 3 Cl atoms on the left and 0 Cl atoms on the right. We can balance it by placing a coefficient of 3 in front of CuSO4 on the right side. - Balanced equation: AlCl3 + 3Ba(OH)2 = CuSO4 + Al(OH)3 + t

4. LiOH + ZnCl2 = Ca(OH)2 + CO2 - Balance Li: There is 1 Li atom on the left and 0 Li atoms on the right. We can balance it by placing a coefficient of 2 in front of LiOH on the left side. - Balance Cl: There are 2 Cl atoms on the left and 0 Cl atoms on the right. We can balance it by placing a coefficient of 2 in front of ZnCl2 on the right side. - Balanced equation: 2LiOH + ZnCl2 = Ca(OH)2 + CO2

5. Ca(OH)2 + HNO3 = LiOH + H2SiO3 - Balance Ca: There is 1 Ca atom on the left and 0 Ca atoms on the right. We can balance it by placing a coefficient of 1 in front of Ca(OH)2 on the right side. - Balance H: There are 4 H atoms on the left and 4 H atoms on the right. It is already balanced. - Balanced equation: Ca(OH)2 + HNO3 = LiOH + H2SiO3

6. NaOH + H2S = t - Balance Na: There is 1 Na atom on the left and 0 Na atoms on the right. We can balance it by placing a coefficient of 2 in front of NaOH on the right side. - Balanced equation: 2NaOH + H2S = t

Please note that the coefficients 't' in the equations represent unknown values that cannot be determined without additional information.