Question

Написать уравнения реакций при помощи которых можно осуществить следующие превращения: Al4C3 ----(+H2O)----> x1-----(+Cl2)-----> x2 (+Na)----> x3----(+O2)----> x4-----(+C)----> x5

Answer 1

Ответ:

Объяснение:

Al4C3 + 12H2O = 4Al(OH)3 + 3CH4

CH4 + Cl2 -> CH3Cl + HCl

CH3Cl + 2Na + Cl-CH3 -> CH3-CH3 + 2NaCl

2CH3-CH3 +7O2 -> 4CO2 + 6H2O

CO2 + C = 2CO

Answer 2

1) al4c3 + 12H2O -> 4Al(OH)3 + 3CH4 EQUATION: Aluminum carbide reacts with water to form aluminum hydroxide and methane gas.

2) 4Al(OH)3 + 3Cl2 -> 2AlCl3 + 6H2O EQUATION: Aluminum hydroxide reacts with chlorine gas to form aluminum chloride and water.

3) 2AlCl3 + 6Na -> 2Al + 6NaCl EQUATION: Aluminum chloride reacts with sodium to form aluminum and sodium chloride.

4) 4Al + 3O2 -> 2Al2O3 EQUATION: Aluminum reacts with oxygen gas to form aluminum oxide.

5) 2Al2O3 + 3C -> 4Al + 3CO2 EQUATION: Aluminum oxide reacts with carbon to form aluminum and carbon dioxide.