Question

Пропен об'ємом 30 л повністю згорів у кисні.Обчисліть об'єм кисню,що витратився,та об'єм карбона (IV) оксиду,що утворився при цьому (н.у.)

Answer 1

Ответ:

Объяснение:

   30 л                      Х л                      Х л

 2C3H6     +           9O2    =              6CO2     +     6H2O

n=2 моль                 n=9 моль             n=6 моль

Vm=22,4 л/моль    Vm=22,4 л/моль  Vm=22,4 л/моль

V = 44,8 л               V =201,6 л              V = 134,4 л

30 л  С3Н6   -   Х л  О2

44,8 л С3Н6  -  201,6 л  О2

V(O2) = 30 * 201,6 / 44,8 = 135 л

30 л  С3Н6   -   Х л   СО2

44,8 л С3Н8  -  134,4 л  СО2

V(CO2) = 30 * 134,4 / 44,8 = 90 л

Answer 2

#### Calculation of Oxygen and Carbon Dioxide Volumes To calculate the volume of oxygen consumed and the volume of carbon dioxide produced when 30 liters of propane fully combusts in oxygen, we need to consider the balanced chemical equation for the combustion reaction of propane. The balanced chemical equation for the combustion of propane is as follows: **C3H8 + 5O2 → 3CO2 + 4H2O** From the balanced equation, we can see that one molecule of propane (C3H8) reacts with five molecules of oxygen (O2) to produce three molecules of carbon dioxide (CO2) and four molecules of water (H2O). To calculate the volume of oxygen consumed, we need to determine the stoichiometric ratio between propane and oxygen. From the balanced equation, we can see that one molecule of propane reacts with five molecules of oxygen. Therefore, the volume of oxygen consumed can be calculated as follows: **Volume of oxygen consumed = (Volume of propane) x (Stoichiometric ratio of oxygen/propane)** Given that the volume of propane is 30 liters, the stoichiometric ratio of oxygen to propane is 5:1. Therefore, the volume of oxygen consumed can be calculated as: **Volume of oxygen consumed = 30 liters x (5/1) = 150 liters** To calculate the volume of carbon dioxide produced, we need to determine the stoichiometric ratio between propane and carbon dioxide. From the balanced equation, we can see that one molecule of propane reacts to produce three molecules of carbon dioxide. Therefore, the volume of carbon dioxide produced can be calculated as follows: **Volume of carbon dioxide produced = (Volume of propane) x (Stoichiometric ratio of carbon dioxide/propane)** Given that the volume of propane is 30 liters, the stoichiometric ratio of carbon dioxide to propane is 3:1. Therefore, the volume of carbon dioxide produced can be calculated as: **Volume of carbon dioxide produced = 30 liters x (3/1) = 90 liters** Therefore, when 30 liters of propane fully combusts in oxygen, approximately 150 liters of oxygen are consumed, and approximately 90 liters of carbon dioxide are produced. [[SOURCE 1]]