Question

6 Закончите уравнения реакций которые идут и расставьте коэффициенты FeO + H2O = CO2 + H2O = SO2 + Na2O = Mg (OH)2 + N2O5 = H3PO4 + CaO = Al2O3 + HCl = KOH + SO3 = SiO2 + H2O =

Answer 1

Ответ:

1)FeO + H2O = Fe(OH)2

2)6CO2 + 6H2O = C6H12O6 + 6O2

  CO2 + H2O = H2CO3

3)SO2 + Na2O = Na2SO3

4)Mg(OH)2 + N2O5 = Mg(NO3)2 + H2O

5)2H3PO4 + 3CaO = Ca3(PO4)2 + 3H2O

6)Al2O3 + 6HCl = 2AlCl3 + 3H2O

7)2KOH + SO3 = K2SO4 + H2O

8)SiO2 + 2H2O = H4SiO4

  SiO2 + H2O = H2SiO3

Объяснение:

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation and balance them one by one.

1. FeO + H2O = CO2 + H2O

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's start with the oxygen atoms:

On the left side, we have 1 oxygen atom in FeO and 1 oxygen atom in H2O, giving us a total of 2 oxygen atoms. On the right side, we have 2 oxygen atoms in CO2 and 1 oxygen atom in H2O, giving us a total of 3 oxygen atoms.

To balance the oxygen atoms, we can add a coefficient of 2 in front of H2O on the left side:

FeO + 2H2O = CO2 + H2O

Now, let's balance the hydrogen atoms:

On the left side, we have 2 hydrogen atoms in 2H2O, giving us a total of 4 hydrogen atoms. On the right side, we have 2 hydrogen atoms in H2O, giving us a total of 2 hydrogen atoms.

To balance the hydrogen atoms, we can add a coefficient of 2 in front of H2O on the right side:

FeO + 2H2O = CO2 + 2H2O

Finally, let's balance the carbon and iron atoms:

On the left side, we have 1 carbon atom in CO2 and 1 iron atom in FeO. On the right side, we have 1 carbon atom in CO2 and 1 iron atom in FeO.

The equation is now balanced:

FeO + 2H2O = CO2 + 2H2O [[1]]

2. SO2 + Na2O = Mg(OH)2 + N2O5

To balance this equation, let's start with the oxygen atoms:

On the left side, we have 2 oxygen atoms in SO2 and 1 oxygen atom in Na2O, giving us a total of 3 oxygen atoms. On the right side, we have 2 oxygen atoms in Mg(OH)2 and 5 oxygen atoms in N2O5, giving us a total of 7 oxygen atoms.

To balance the oxygen atoms, we can add a coefficient of 2 in front of Na2O on the left side:

SO2 + 2Na2O = Mg(OH)2 + N2O5

Now, let's balance the sodium atoms:

On the left side, we have 4 sodium atoms in 2Na2O. On the right side, we have 2 sodium atoms in Mg(OH)2.

To balance the sodium atoms, we can add a coefficient of 2 in front of Mg(OH)2 on the right side:

SO2 + 2Na2O = 2Mg(OH)2 + N2O5

Finally, let's balance the sulfur, nitrogen, hydrogen, and oxygen atoms:

On the left side, we have 1 sulfur atom in SO2 and 5 oxygen atoms in N2O5. On the right side, we have 1 sulfur atom in Mg(OH)2 and 7 oxygen atoms in Mg(OH)2.

The equation is now balanced:

SO2 + 2Na2O = 2Mg(OH)2 + N2O5 [[2]]

3. H3PO4 + CaO = Al2O3 + HCl + KOH

To balance this equation, let's start with the hydrogen atoms:

On the left side, we have 3 hydrogen atoms in H3PO4 and 1 hydrogen atom in HCl, giving us a total of 4 hydrogen atoms. On the right side, we have 1 hydrogen atom in KOH.

To balance the hydrogen atoms, we can add a coefficient of 4 in front of KOH on the right side:

H3PO4 + CaO = Al2O3 + HCl + 4KOH

Now, let's balance the phosphorus, calcium, aluminum, chlorine, and oxygen atoms:

On the left side, we have 1 phosphorus atom in H3PO4, 1 calcium atom in CaO, and 1 aluminum atom in Al2O3. On the right side, we have 1 chlorine atom in HCl and 4 potassium atoms in 4KOH.

To balance the phosphorus, calcium, aluminum, chlorine, and oxygen atoms, we can add a coefficient of 2 in front of Al2O3 on the right side:

H3PO4 + CaO = 2Al2O3 + HCl + 4KOH

The equation is now balanced:

H3PO4 + CaO = 2Al2O3 + HCl + 4KOH [[3]]

4. SO3 + SiO2 + H2O = ?

The equation provided is incomplete. We need to know the products of the reaction in order to balance it properly. Please provide the missing information.

Please let me know if you have any further questions!