Question

Даю 98 баллов При взаимодействии 56г азота с водородом получили 48г аммиака.Определите массовую долю выхода аммиака от теоретически возможного

Answer 1

Лови :)
С наступающим ,хохо

Answer 2

Calculation of the Theoretical Yield of Ammonia

To determine the mass fraction of the ammonia obtained compared to the theoretically possible yield, we need to calculate the theoretical yield of ammonia first.

Given: - Mass of nitrogen (N2) = 56 g - Mass of hydrogen (H2) = 48 g - Mass of ammonia (NH3) obtained = 48 g

The balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia is:

N2 + 3H2 → 2NH3

From the balanced equation, we can see that the molar ratio between nitrogen and ammonia is 1:2. This means that for every 1 mole of nitrogen, we should obtain 2 moles of ammonia.

To calculate the theoretical yield of ammonia, we need to convert the masses of nitrogen and ammonia to moles using their molar masses.

The molar mass of nitrogen (N2) is 28 g/mol, and the molar mass of ammonia (NH3) is 17 g/mol.

Number of moles of nitrogen: moles of N2 = mass of N2 / molar mass of N2 moles of N2 = 56 g / 28 g/mol moles of N2 = 2 mol

According to the balanced equation, the number of moles of ammonia should be twice the number of moles of nitrogen.

Number of moles of ammonia: moles of NH3 = 2 * moles of N2 moles of NH3 = 2 * 2 mol moles of NH3 = 4 mol

Now, we can calculate the theoretical yield of ammonia in grams.

Theoretical yield of ammonia: mass of NH3 = moles of NH3 * molar mass of NH3 mass of NH3 = 4 mol * 17 g/mol mass of NH3 = 68 g

Calculation of the Mass Fraction of Ammonia Obtained

To determine the mass fraction of ammonia obtained compared to the theoretically possible yield, we divide the mass of ammonia obtained by the theoretical yield and multiply by 100.

Mass fraction of ammonia obtained: mass fraction = (mass of NH3 obtained / theoretical yield of NH3) * 100 mass fraction = (48 g / 68 g) * 100 mass fraction ≈ 70.59%

Therefore, the mass fraction of ammonia obtained compared to the theoretically possible yield is approximately 70.59%.

Please note that the calculations provided are based on the given information and assumptions.