Question

M(H2)=4гр m(O2)=24гр m(H2O)-? ​

Answer 1

Объяснение:

2H2+O2=2H2O

решаем по недостатку

Answer 2

To find the mass of water (H2O) produced when hydrogen (H2) reacts with oxygen (O2), you can use the balanced chemical equation for the reaction:

2H2 + O2 -> 2H2O

In this equation, it shows that 2 moles of hydrogen (H2) react with 1 mole of oxygen (O2) to produce 2 moles of water (H2O).

First, you need to calculate the number of moles of hydrogen (H2) and oxygen (O2) based on their given masses:

1. Moles of H2: Moles = Mass (g) / Molar Mass (g/mol) Moles of H2 = 4 g / 2 g/mol = 2 moles

2. Moles of O2: Moles = Mass (g) / Molar Mass (g/mol) Moles of O2 = 24 g / 32 g/mol = 0.75 moles

Now that you have the moles of both reactants, you can use the stoichiometry of the balanced equation to find the moles of water (H2O) produced. According to the equation, 2 moles of H2 produce 2 moles of H2O, so the ratio is 1:1.

3. Moles of H2O = Moles of H2 (since they react in a 1:1 ratio) = 2 moles

Finally, you can calculate the mass of water (H2O) produced using the moles and the molar mass of water:

Molar Mass of H2O (g/mol) = 2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

Mass of H2O (g) = Moles of H2O × Molar Mass of H2O Mass of H2O = 2 moles × 18.02 g/mol ≈ 36.04 g

So, the mass of water (H2O) produced is approximately 36.04 grams.