Question

Cu(OH)2 → CuO → CuSO4 → Cu(NO3)2 → Cu(OH)2

Answer 1

Ответ:

1)Cu(OH)2=CuO+H2O

2)CuO+H2SO4=CuSO4+H2O

3)CuSO4+Ba(NO3)2=BaSO4(осадок)+Cu(NO3)2

4)Cu(NO3)2+2NaOH=Cu(OH)2+2NaNO3

Объяснение:

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Answer 2

It looks like you've provided a sequence of chemical reactions involving copper compounds. Let me break down the reactions for you:

1. Cu(OH)2 (Copper(II) hydroxide) → CuO (Copper(II) oxide): Copper(II) hydroxide decomposes upon heating to form copper(II) oxide and water: Cu(OH)2 → CuO + H2O

2. CuO (Copper(II) oxide) → CuSO4 (Copper(II) sulfate): Copper(II) oxide reacts with sulfuric acid to form copper(II) sulfate and water: CuO + H2SO4 → CuSO4 + H2O

3. CuSO4 (Copper(II) sulfate) → Cu(NO3)2 (Copper(II) nitrate): Copper(II) sulfate reacts with nitric acid to form copper(II) nitrate and a byproduct: CuSO4 + 2HNO3 → Cu(NO3)2 + H2SO4

4. Cu(NO3)2 (Copper(II) nitrate) → Cu(OH)2 (Copper(II) hydroxide): Copper(II) nitrate reacts with sodium hydroxide to form copper(II) hydroxide and sodium nitrate: Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3

This sequence of reactions demonstrates the transformation of copper compounds from copper(II) hydroxide to copper(II) oxide, then to copper(II) sulfate, followed by copper(II) nitrate, and finally back to copper(II) hydroxide. It's important to note that the chemical reactions you've listed involve specific reactants and conditions, so these reactions might not occur under all circumstances.