Question

M(CuO) = 16 г. m(CuSO4) - ?

Answer 1

Дано:

m(CuO) =16г

Найти:

m(CuSO4)=?

Решение:

CuO+H2SO4=CuSO4+H2O

n(CuO) =m/M=16г:80г/моль =0,2моль

M(CuO) =64+16=80г/моль

n(CuO)=n(CuSO4)=0,2моль

m(CuSO4)=n*M=0,2моль*160г/моль=32г

M(CuSO4)=64+32+16*4=160г/моль

Answer 2

To calculate the molar mass of copper(II) sulfate (CuSO4), you need to consider the molar masses of all the individual elements in the compound. Copper(II) sulfate consists of one copper (Cu) atom, one sulfur (S) atom, and four oxygen (O) atoms. You can find the molar masses of these elements on the periodic table:

• Molar mass of Cu (copper): 63.55 g/mol
• Molar mass of S (sulfur): 32.07 g/mol
• Molar mass of O (oxygen): 16.00 g/mol

Now, add up the molar masses of each element in CuSO4:

M(CuSO4) = (1 * M(Cu)) + (1 * M(S)) + (4 * M(O)) M(CuSO4) = (1 * 63.55 g/mol) + (1 * 32.07 g/mol) + (4 * 16.00 g/mol)

M(CuSO4) = 63.55 g/mol + 32.07 g/mol + 64.00 g/mol

M(CuSO4) = 159.62 g/mol

So, the molar mass of copper(II) sulfate (CuSO4) is 159.62 grams per mole.