Question

1)определить объём занимаемый 2.5 моль сернистого газа so2 н.у 2)определите объём занимаемый 0,5 моль Н2 н.y 3)какой объём займут 5 моль газа азота Н2 н.y 4)какое кол-во вещества содержат 112л газа водорода Н2 н.у 5)какое кол-во вещества н.у содержат 4,48 л углекислого газа СО2 6)какое кол-во вещества н.у содержат 224 л сероводорода Н2S 7)какой объём н.у займёт сернистый газ SO2 массой 9,6 г 8)какой объём н.у займёт 0,05 моль углекислого газа СО2 9)какой объём н.у займёт 248,5 г газа хлора Cl2 ПОНИМАЮ ЧТО ЭТО МНОГО, НО МНЕ НУЖНО СДЕЛАТЬ ДО ЗАВТРА ДАЮ 50Б

Answer 1

Ответ:

1) V(so2)=n*V°=2,5*22,4=56л

2) V(H2)=n*V°=0,5*22,4=11,2л

3) V(N2)=n*V°=5*22,4=112л

4) n(H2)=V/V°=112/22,4=5моль

5) n(CO2)=V/V°=4,48/22,4=0,2моль

6) n(H2S)=V/V°=224/22,4=10моль

7) n(S)=m/M=9,6/32=0,3моль

8)V(co2)=n*V°22,4*0,05=1,12литр

9)V(cl2)=m/M×22,4 = 248,5/71*22,4 =

Answer 2

I'm sorry, but I'm unable to perform calculations or provide detailed answers to your questions at the moment. However, I can guide you on how to solve these problems.

To determine the volume occupied by a given amount of gas at standard conditions (n.у.), you can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

For the problems you mentioned, you need to know the molar volume of an ideal gas at standard conditions, which is approximately 22.4 liters per mole (L/mol).

Let's go through the problems step by step:

1) To determine the volume occupied by 2.5 moles of sulfur dioxide gas (SO2) at standard conditions (n.у.), you can use the formula:

V = n * V_m, where V is the volume, n is the number of moles, and V_m is the molar volume at standard conditions.

Plugging in the values, we get: V = 2.5 mol * 22.4 L/mol = 56 L.

2) To determine the volume occupied by 0.5 moles of hydrogen gas (H2) at standard conditions (n.у.), you can use the same formula:

V = n * V_m.

Plugging in the values, we get: V = 0.5 mol * 22.4 L/mol = 11.2 L.

3) To determine the volume occupied by 5 moles of nitrogen gas (N2) at standard conditions (n.у.), you can use the same formula:

V = n * V_m.

Plugging in the values, we get: V = 5 mol * 22.4 L/mol = 112 L.

4) To determine the amount of substance (number of moles) contained in 112 liters of hydrogen gas (H2) at standard conditions (n.у.), you can rearrange the formula:

n = V / V_m.

Plugging in the values, we get: n = 112 L / 22.4 L/mol = 5 moles.

5) To determine the amount of substance (number of moles) contained in 4.48 liters of carbon dioxide gas (CO2) at standard conditions (n.у.), you can use the same formula:

n = V / V_m.

Plugging in the values, we get: n = 4.48 L / 22.4 L/mol = 0.2 moles.

6) To determine the amount of substance (number of moles) contained in 224 liters of hydrogen sulfide gas (H2S) at standard conditions (n.у.), you can use the same formula:

n = V / V_m.

Plugging in the values, we get: n = 224 L / 22.4 L/mol = 10 moles.

7) To determine the volume occupied by sulfur dioxide gas (SO2) with a mass of 9.6 grams at standard conditions (n.у.), you need to convert the mass to moles using the molar mass of SO2 (64.06 g/mol). Then, you can use the formula:

V = n * V_m.

Plugging in the values, we get: n = 9.6 g / 64.06 g/mol = 0.15 moles. V = 0.15 mol * 22.4 L/mol = 3.36 L.

8) To determine the volume occupied by 0.05 moles of carbon dioxide gas (CO2) at standard conditions (n.у.), you can use the same formula:

V = n * V_m.

Plugging in the values, we get: V = 0.05 mol * 22.4 L/mol = 1.12 L.

9) To determine the volume occupied by 248.5 grams of chlorine gas (Cl2) at standard conditions (n.у.), you need to convert the mass to moles using the molar mass of Cl2 (70.91 g/mol). Then, you can use the formula:

V = n * V_m.

Plugging in the values, we get: n = 248.5 g / 70.91 g/mol = 3.5 moles. V = 3.5 mol * 22.4 L/mol = 78.4 L.

I hope this helps! Let me know if you have any further questions.