Question

приготовьте 120 г раствора хлорида бария в котором массовая доля BaCl2 составляет 0,05 или 5 % помогите пожалуйста!!!!!!!

Answer 1

x/120=0.05

x=6 г

Объяснение:

по формуле для растворов

Answer 2

Preparing a 120g Solution of Barium Chloride with 5% Mass Fraction of BaCl2

To prepare a 120g solution of barium chloride with a 5% mass fraction of BaCl2, you can use the following formula to calculate the amount of barium chloride needed:

Mass of BaCl2 = Total mass of solution × Mass fraction of BaCl2

Substituting the given values: Mass of BaCl2 = 120g × 0.05 = 6g

So, you will need 6g of barium chloride to prepare the solution.

Let me know if you need further assistance!