Question

Рассчитайте массу и количество оксида натрия которая образуется при сгорании 12 г натрия

Answer 1

4Na + O2 ⇒ 2Na2O

Посчитаем, сколько сгорело натрия и образовалось оксида натрия в этом уравнении:

Mr(Na) = 23 г/моль

m(Na) = Mr * n = 23 * 4 = 92 г

Mr(Na2O) = 23 * 2 + 16 = 62 г/моль

m(Na2О) = Mr * n = 62 * 2 = 124 г

Составим пропорцию. Если при сгорании 92 г натрия выделилось 124 г оксида натрия, то при сгорании 12 г натрия выделится Х г оксида натрия.

92 г (Na) - 124 г (Na2O)

12 г (Na) - Х г (Na2O)

Составим уравнение:

Х = 12 * 124 / 92 ≅ 16,17 г

Зная молярную массу и массу, можно найти количество вещества:

n(Na2O) = m / Mr = 16,17 / 62 ≅ 0,26 моль

Answer 2

Calculation of the Mass and Quantity of Sodium Oxide Formed

To calculate the mass and quantity of sodium oxide formed during the combustion of 12 grams of sodium, we need to consider the balanced chemical equation for the reaction.

The balanced chemical equation for the combustion of sodium is:

2Na + O2 -> 2Na2O

From the equation, we can see that 2 moles of sodium react with 1 mole of oxygen gas to produce 2 moles of sodium oxide.

To calculate the mass of sodium oxide formed, we need to determine the molar mass of sodium oxide (Na2O). The molar mass of sodium (Na) is approximately 22.99 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.

The molar mass of sodium oxide (Na2O) can be calculated as follows:

2(22.99 g/mol) + 16.00 g/mol = 61.98 g/mol

Now, we can calculate the mass of sodium oxide formed:

Mass of sodium oxide = (Molar mass of Na2O) * (Number of moles of Na2O)

To find the number of moles of sodium oxide formed, we need to determine the number of moles of sodium (Na) present in 12 grams of sodium.

Number of moles of sodium = (Mass of sodium) / (Molar mass of sodium)

Number of moles of sodium = 12 g / 22.99 g/mol

Now, we can calculate the number of moles of sodium oxide formed:

Number of moles of sodium oxide = (Number of moles of sodium) / 2

Finally, we can calculate the mass of sodium oxide formed:

Mass of sodium oxide = (Molar mass of Na2O) * (Number of moles of Na2O)

Let's calculate the mass and quantity of sodium oxide formed using the given information.

Calculation:

Number of moles of sodium = 12 g / 22.99 g/mol = 0.522 mol Number of moles of sodium oxide = (Number of moles of sodium) / 2 = 0.522 mol / 2 = 0.261 mol

Mass of sodium oxide = (Molar mass of Na2O) * (Number of moles of Na2O) = 61.98 g/mol * 0.261 mol = 16.17 g

Therefore, the mass of sodium oxide formed during the combustion of 12 grams of sodium is approximately 16.17 grams, and the quantity of sodium oxide formed is approximately 0.261 moles.

Please note that the values calculated above are approximate and may vary slightly depending on the actual molar masses used.

I hope this helps! Let me know if you have any further questions.