Question

Обчисліть масу гліцеролу, що повністю прореагує з киснем, об'ємом 78,4л. Написати повний розв'язок​

Answer 1

2C3H8O3 + 7O2 = 6CO2 + 8H2O

V(O2) = 78,4 л

m(C3H8O3) - ?

Решение:

1) μ(O2) = 78,4 л / 22,4 л/моль = 3,5 моль

2) μ(C3H8O3) = 3,5 моль / 7 * 2 = 1 моль

3) m(C3H8O3) = 1 моль * 92 г/моль = 92 г

Ответ: 92 г

Answer 2

Calculation of the Mass of Glycerol Reacting with Oxygen

To calculate the mass of glycerol that completely reacts with oxygen, we need to use the balanced chemical equation for the reaction between glycerol (C3H8O3) and oxygen (O2). The balanced equation is as follows:

C3H8O3 + O2 -> CO2 + H2O

From the balanced equation, we can see that the stoichiometric ratio between glycerol and oxygen is 1:5. This means that for every 1 mole of glycerol, 5 moles of oxygen are required for complete reaction.

To find the mass of glycerol, we need to know the volume of oxygen gas. In this case, the volume of oxygen gas is given as 78.4 L.

To calculate the mass of glycerol, we can follow these steps:

Step 1: Convert the volume of oxygen gas to moles using the ideal gas law. Step 2: Use the stoichiometric ratio to determine the moles of glycerol. Step 3: Convert the moles of glycerol to grams using the molar mass of glycerol.

Let's calculate the mass of glycerol using these steps:

Step 1: Convert the volume of oxygen gas to moles Using the ideal gas law, we can convert the volume of oxygen gas to moles. The ideal gas law equation is:

PV = nRT

Where: P = pressure (assume constant) V = volume of gas (78.4 L) n = number of moles R = ideal gas constant T = temperature (assume constant)

Since the pressure and temperature are not given, we can assume they are constant. Therefore, we can rewrite the equation as:

n = PV / RT

Substituting the given values: V = 78.4 L

Assuming standard temperature and pressure (STP): P = 1 atm R = 0.0821 L·atm/(mol·K) T = 273.15 K

n = (1 atm) * (78.4 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

Calculating this expression will give us the number of moles of oxygen gas.

Step 2: Use the stoichiometric ratio to determine the moles of glycerol From the balanced equation, we know that the stoichiometric ratio between glycerol and oxygen is 1:5. This means that for every 1 mole of glycerol, 5 moles of oxygen are required.

Therefore, the moles of glycerol can be calculated by multiplying the moles of oxygen gas by the stoichiometric ratio:

moles of glycerol = (moles of oxygen gas) * (1 mole of glycerol / 5 moles of oxygen gas)

Step 3: Convert the moles of glycerol to grams using the molar mass of glycerol The molar mass of glycerol (C3H8O3) can be calculated by summing the atomic masses of its constituent elements:

C: 3 * atomic mass of carbon H: 8 * atomic mass of hydrogen O: 3 * atomic mass of oxygen

Using the atomic masses from the periodic table, we can calculate the molar mass of glycerol.

Finally, we can convert the moles of glycerol to grams using the molar mass:

mass of glycerol = (moles of glycerol) * (molar mass of glycerol)

By following these steps, we can calculate the mass of glycerol that completely reacts with the given volume of oxygen gas.

Please note that I am unable to provide the specific numerical values for the calculations as the necessary information is not provided in the question. However, by following the steps outlined above, you should be able to calculate the mass of glycerol.