Question

в коробці лежить 60 сірниківза 1 хід можна взяти від 1-5 сірниківпрограє той хто не зможе зробити хітхто з гравців прерший чи другий зможе забеспечить собі перемогу

Answer 1

This is a mathematical puzzle that involves strategy and logic. The question is: In a box there are 60 matches. For one move, you can take from 1 to 5 matches. The one who cannot make a move loses. Who of the two players, first or second, can ensure their victory?

The answer is: The first player can ensure their victory by following a simple rule. The rule is: always take the number of matches that makes the remaining number divisible by 6. For example, if there are 60 matches, the first player can take 4 matches, leaving 56. Then, no matter how many matches the second player takes (from 1 to 5), the first player can take the rest to make the remaining number divisible by 6 again. For example, if the second player takes 3 matches, leaving 53, the first player can take 5 matches, leaving 48. This way, the first player can always force the second player to face a situation where there are only 6 matches left, and then take 5 matches, leaving 1 match for the second player to lose.

This strategy is based on the observation that if the number of matches is divisible by 6, then the player who faces this situation cannot win, because no matter how many matches they take, the other player can take the rest to make the number divisible by 6 again. Therefore, the first player can ensure their victory by always creating this situation for the second player.

You can find more details and examples of this puzzle in the web search results . I hope this helps you understand the solution.