Question

Решите уравнение 1) 3х^3-108х=0 2) 121х^3-22х^2+х=0 3) х^3-2х^2-9х+18=0 Решите подалуйста Срочно )))))

Answer 1

Держи!!) хороших тебе оценок)) не забудь поставить лайк!)

Answer 2

Solving the Equations

Let's solve the given equations one by one:

1) Equation: 3x^3 - 108x = 0

To solve this equation, we can factor out the common factor of x:

x(3x^2 - 108) = 0

Now, we have two factors: x = 0 and 3x^2 - 108 = 0.

For the second factor, we can solve for x by dividing both sides of the equation by 3:

3x^2 - 108 = 0 x^2 - 36 = 0 (x - 6)(x + 6) = 0

So, the solutions for this equation are x = 0, x = 6, and x = -6.

2) Equation: 121x^3 - 22x^2 + x = 0

To solve this equation, we can factor out the common factor of x:

x(121x^2 - 22x + 1) = 0

Now, we have two factors: x = 0 and 121x^2 - 22x + 1 = 0.

For the second factor, we can solve for x using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 121, b = -22, and c = 1. Substituting these values into the quadratic formula, we get:

x = (-(-22) ± √((-22)^2 - 4(121)(1))) / (2(121)) x = (22 ± √(484 - 484)) / 242 x = (22 ± √0) / 242 x = 22 / 242 x = 1/11

So, the solutions for this equation are x = 0 and x = 1/11.

3) Equation: x^3 - 2x^2 - 9x + 18 = 0

To solve this equation, we can use various methods such as factoring, synthetic division, or the rational root theorem. In this case, let's try factoring by grouping:

x^3 - 2x^2 - 9x + 18 = 0 (x^3 - 2x^2) + (-9x + 18) = 0 x^2(x - 2) - 9(x - 2) = 0 (x^2 - 9)(x - 2) = 0

Now, we have two factors: x^2 - 9 = 0 and x - 2 = 0.

For the first factor, we can factor it further using the difference of squares:

(x + 3)(x - 3)(x - 2) =