Вопрос задан 12.05.2019 в 10:59. Предмет Алгебра. Спрашивает Нігда Оля.

1 5/7:1 1/7; 3 1/5:2 2/15; 5 2/3:1/3-1 7/12×6; помогите пожалуйста.

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Отвечает Малютин Слава.
15/11; 93/22 ; 0,5
Или тебе нужно с полным решение?
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation 1: 1 + 5/7 : 1 + 1/7

To solve this calculation, we need to follow the order of operations (PEMDAS/BODMAS). First, we perform the division, and then we perform the addition.

1 + 5/7 : 1 + 1/7 = 1 + (5/7) / (1 + 1/7)

To simplify the division, we need to find a common denominator for the fractions involved.

The common denominator for 7 and 1 is 7. So, we have:

1 + (5/7) / (1 + 1/7) = 1 + (5/7) / (7/7 + 1/7) = 1 + (5/7) / (8/7)

Now, we can perform the division:

1 + (5/7) / (8/7) = 1 + (5/7) * (7/8) = 1 + (5 * 7) / (7 * 8) = 1 + 35/56

To simplify the addition, we need to find a common denominator for 1 and 35/56.

The common denominator for 1 and 35/56 is 56. So, we have:

1 + 35/56 = (56/56) + 35/56 = 91/56

Therefore, the result of the calculation 1 + 5/7 : 1 + 1/7 is 91/56.

Calculation 2: 3 + 1/5 : 2 + 2/15

Similar to the previous calculation, we need to follow the order of operations (PEMDAS/BODMAS). First, we perform the division, and then we perform the addition.

3 + 1/5 : 2 + 2/15 = 3 + (1/5) / (2 + 2/15)

To simplify the division, we need to find a common denominator for the fractions involved.

The common denominator for 5 and 15 is 15. So, we have:

3 + (1/5) / (2 + 2/15) = 3 + (1/5) / (30/15 + 2/15) = 3 + (1/5) / (32/15)

Now, we can perform the division:

3 + (1/5) / (32/15) = 3 + (1/5) * (15/32) = 3 + (1 * 15) / (5 * 32) = 3 + 15/160

To simplify the addition, we need to find a common denominator for 3 and 15/160.

The common denominator for 3 and 15/160 is 160. So, we have:

3 + 15/160 = (480/160) + 15/160 = 495/160

Therefore, the result of the calculation 3 + 1/5 : 2 + 2/15 is 495/160.

Calculation 3: 5 + 2/3 : 1/3 - 1 + 7/12 × 6

Again, we need to follow the order of operations (PEMDAS/BODMAS). First, we perform the multiplication, then the division, and finally the addition and subtraction.

5 + 2/3 : 1/3 - 1 + 7/12 × 6 = 5 + (2/3) : (1/3) - 1 + (7/12) × 6

To simplify the division, we need to invert the divisor and multiply:

5 + (2/3) : (1/3) - 1 + (7/12) × 6 = 5 + (2/3) × (3/1) - 1 + (7/12) × 6 = 5 + (2 × 3) / (3 × 1) - 1 + (7/12) × 6 = 5 + 6/3 - 1 + (7/12) × 6 = 5 + 2 - 1 + (7/12) × 6 = 5 + 2 - 1 + (7 × 6) / 12 = 5 + 2 - 1 + 42/12

To simplify the addition and subtraction, we need to find a common denominator for the fractions involved.

The common denominator for 12 and 1 is 12. So, we have:

5 + 2 - 1 + 42/12 = (5 × 12) / 12 + 2 - 1 + 42/12 = 60/12 + 2 - 1 + 42/12 = 5 + 2 - 1 + 42/12

Now, we can perform the addition and subtraction:

5 + 2 - 1 + 42/12 = 5 + 2 - 1 + 42/12 = 6 + 42/12 = 6 + (3 × 14) / (3 × 4) = 6 + 14/4 = 6 + 7/2 = (6 × 2) / 2 + 7/2 = 12/2 + 7/2 = 19/2

Therefore, the result of the calculation 5 + 2/3 : 1/3 - 1 + 7/12 × 6 is 19/2.

I hope this helps! Let me know if you have any further questions.

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