Question

1) -i√5*4i√5; 2) (3-2i)(5+4i)-7i+1 УПРОСТИТЕ ПОЖАЛУЙСТА, ОЧЕНЬ НАДО

Answer 1

Ответ в приложении *&/$#@!*&/$#@!

Answer 2

1) To simplify the expression -i√5 * 4i√5, we can first simplify each term separately and then multiply them together.

The term -i√5 can be simplified as follows: -i√5 = -i * √5 = -√5i

The term 4i√5 can be simplified as follows: 4i√5 = 4i * √5 = 4√5i

Now, we can multiply the simplified terms together: (-√5i) * (4√5i) = -4 * 5 * i * i = -20 * i^2

Since i^2 is equal to -1, we can simplify further: -20 * i^2 = -20 * (-1) = 20

Therefore, the simplified expression -i√5 * 4i√5 is equal to 20.

2) To simplify the expression (3-2i)(5+4i)-7i+1, we can use the distributive property to multiply the terms.

First, let's multiply the terms (3-2i) and (5+4i): (3-2i)(5+4i) = 3 * 5 + 3 * 4i - 2i * 5 - 2i * 4i = 15 + 12i - 10i - 8i^2

Since i^2 is equal to -1, we can simplify further: 15 + 12i - 10i - 8i^2 = 15 + 2i - 8(-1) = 15 + 2i + 8 = 23 + 2i

Next, let's simplify the terms -7i and 1: -7i + 1 = 1 - 7i

Finally, let's add the simplified terms together: (23 + 2i) + (1 - 7i) = 23 + 1 + 2i - 7i = 24 - 5i

Therefore, the simplified expression (3-2i)(5+4i)-7i+1 is equal to 24 - 5i.

I hope this helps! Let me know if you have any further questions.