Question

Найдите корень уравнения (x+3)(x-7)-(x-4)(x+4)=11 помогите

Answer 1

X²-7x+2x-21-x²+16=11
-5x=16
x=-3,2

Answer 2

Solving the Equation

To find the root of the equation (x+3)(x-7)-(x-4)(x+4)=11, we can start by expanding the equation and simplifying it.

Expanding the equation, we get:

(x+3)(x-7)-(x-4)(x+4) = 11

Simplifying further, we have:

x^2 - 7x + 3x - 21 - (x^2 + 4x - 4x - 16) = 11

Combining like terms, we get:

x^2 - 4x - 21 - x^2 - 16 = 11

Simplifying again, we have:

-4x - 37 = 11

To isolate the variable, we can add 37 to both sides of the equation:

-4x = 11 + 37

Simplifying further, we get:

-4x = 48

Finally, to solve for x, we divide both sides of the equation by -4:

x = -48/4

Simplifying the division, we find:

x = -12

Therefore, the root of the equation (x+3)(x-7)-(x-4)(x+4)=11 is x = -12.

Answer

The root of the equation (x+3)(x-7)-(x-4)(x+4)=11 is x = -12.