Question

Люди помогите решить номер по алгебре (a-3) (a+2)-a (2a+5)=a квадрат + 2a-3a-6-2a квадрат -5a по формуле сокращённого умножения

Answer 1

Ответ : а равно 6
Если неправильно сорри

Answer 2

Solving the Algebraic Equation

To solve the given algebraic equation (a-3)+(a+2)-a+(2a+5)=a^2+2a-3a-6-2a^2-5a using the formula for the distributive property, we can follow these steps:

1. Simplify both sides of the equation by applying the distributive property and combining like terms. 2. Collect all the terms on one side of the equation and simplify further. 3. Solve for the variable a.

Let's go through each step in detail.

Step 1: Simplify the equation using the distributive property and combine like terms.

(a-3)+(a+2)-a+(2a+5)=a^2+2a-3a-6-2a^2-5a

Expanding the parentheses and combining like terms, we get:

a - 3 + a + 2 - a + 2a + 5 = a^2 + 2a - 3a - 6 - 2a^2 - 5a

Simplifying further, we have:

3a + 4 = -a^2 - 6a - 6

Step 2: Collect all the terms on one side of the equation and simplify further.

To collect all the terms on one side, we can add a^2 + 6a + 6 to both sides of the equation:

3a + 4 + a^2 + 6a + 6 = -a^2 - 6a - 6 + a^2 + 6a + 6

Simplifying, we get:

a^2 + 10a + 10 = 0

Step 3: Solve for the variable a.

To solve the quadratic equation a^2 + 10a + 10 = 0, we can use the quadratic formula:

a = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 10, and c = 10.

Substituting the values into the quadratic formula, we have:

a = (-10 ± √(10^2 - 4 * 1 * 10)) / (2 * 1)

Simplifying further, we get:

a = (-10 ± √(100 - 40)) / 2

a = (-10 ± √60) / 2

a = (-10 ± 2√15) / 2

Simplifying the expression, we have:

a = -5 ± √15

Therefore, the solutions to the given algebraic equation are:

a = -5 + √15 and a = -5 - √15.

Please note that the solutions may vary depending on the context and the specific instructions given for the equation.

I hope this helps! Let me know if you have any further questions.