Question

Арифметическая прогрессия задана условием a4=1/24. q=-0.5. Найти S6?

Answer 1

$a_n=a_1+(n-1)q; a_4= \frac{1}{24} \\ a_1= a_n-(n-1)q ; a_1= \frac{1}{24}-3*(-0.5)= \frac{37}{24} \\ S_n= \frac{2a_1+(n-1)q}{2}n; S_6= \frac{2* \frac{37}{24}+5*(-0.5) }{2}6= \frac{7}{4}=1.75$

Answer 2

Arithmetic Progression and Finding S6

To find the sum of the first six terms (S6) of an arithmetic progression, we need to know the first term (a1), the common difference (d), and the number of terms (n). However, in the given question, only the fourth term (a4) and the common ratio (q) are provided. Without the first term or the common difference, it is not possible to find the sum of the first six terms.

Please provide the first term (a1) or the common difference (d) so that we can calculate S6.