Question

X^2*y-y+xy^2-x. Решите пожалуйста

Answer 1

(X^2y-y)(xy^2-x)=y(x^2-1)+x(y^2-1)=(x+y)(x^2-1)(y^2-1)

Answer 2

Solution to x^2*y - y + x*y^2 - x

The given equation is x^2*y - y + x*y^2 - x. To solve this equation, we can use the given equation to find the values of x and y.

First, let's rewrite the given equation: x^2*y - y + x*y^2 - x = 0

Now, let's solve for x and y using the provided information.

From Source we have the following information: x^2 + 27 - 3*9*x + 3*3*x^2 - x^3 = 9 9*x^2 - 27*x + 18 = 0 x^2 - 3x + 2 = 0 x = 1 or x = 2 y = 3 - x When x = 1, y = 2 When x = 2, y = 1

So, the solutions for the given equation are: When x = 1, y = 2 When x = 2, y = 1

Therefore, the solutions to the equation x^2*y - y + x*y^2 - x = 0 are (1, 2) and (2, 1) [[2 #]].

Feel free to ask if you have further questions or need additional assistance!