Question

Помогите решить срочно! 14/(x-1)+32/(x)=6

Answer 1

Ноз: (x-1)x
$14x+32x-32- x^{2} -x =0$
одз: $x \neq 0 , x \neq 1$
т виета 
$\left \{ {{x_{1} + x_{2} =-46} \atop { x_{2}*x_{1} =-32}} \right.$

Answer 2

Фоточка тебе в помощь ;)

Answer 3

I can help you with your math problem. Here are the steps to solve it:

1. Multiply both sides of the equation by $$x(x-1)$$ to get rid of the fractions. You will get $$14x + 32(x-1) = 6x(x-1)$$. 2. Expand the brackets and simplify the equation. You will get $$-6x^2 + 46x - 38 = 0$$. 3. Use the quadratic formula to find the values of $$x$$ that satisfy the equation. You will get $$x = \frac{-46 \pm \sqrt{46^2 - 4(-6)(-38)}}{2(-6)}$$. 4. Simplify the expression under the square root. You will get $$x = \frac{-46 \pm \sqrt{64}}{-12}$$. 5. Simplify the expression further. You will get $$x = \frac{-23 \pm 4}{-6}$$. 6. Find the two possible values of $$x$$ by choosing either the plus or the minus sign. You will get $$x = \frac{-19}{-6}$$ or $$x = \frac{-27}{-6}$$. 7. Simplify the fractions. You will get $$x = \frac{19}{6}$$ or $$x = \frac{9}{2}$$.

These are the solutions to your equation. However, you need to check if any of them make the original equation undefined. Remember that you cannot divide by zero.

8. Plug in $$x = \frac{19}{6}$$ into the original equation. You will get $$\frac{14}{\frac{19}{6} - 1} + \frac{32}{\frac{19}{6}} = 6$$. This is a valid solution because none of the denominators are zero. 9. Plug in $$x = \frac{9}{2}$$ into the original equation. You will get $$\frac{14}{\frac{9}{2} - 1} + \frac{32}{\frac{9}{2}} = 6$$. This is not a valid solution because the first denominator is zero.

Therefore, the only solution to your equation is $$x = \frac{19}{6}$$. I hope this helps you. Have a nice day.Ответь+подробно.+Помогите+решить+срочно!+14/(x-1)+32/(x)=6