Question

Задайте с помощью рекуррентного соотношения последовательность четных натуральных чисел делящихся на 37.Помогите пожалуйста очень надо!

Answer 1

напр. так

$a_1=74;a_{n+1}=a_n+74$

 

 

Answer 2

Generating a Sequence of Even Natural Numbers Divisible by 37 Using a Recursive Relation

To generate a sequence of even natural numbers that are divisible by 37, we can use a recursive relation. Let's denote the nth term of the sequence as a_n.

To find the recursive relation, we can observe that each term in the sequence is obtained by adding a constant value to the previous term. In this case, the constant value is 74 (since we are looking for even numbers divisible by 37).

Therefore, the recursive relation for the sequence can be defined as:

a_n = a_n-1 + 74

To start the sequence, we need an initial term. Let's choose the first term, a₁, as 74.

Using this recursive relation, we can generate the sequence of even natural numbers divisible by 37 as follows:

a₁ = 74

a₂ = a₁ + 74 = 74 + 74 = 148

a₃ = a₂ + 74 = 148 + 74 = 222

a₄ = a₃ + 74 = 222 + 74 = 296

And so on.

We can continue this process to generate as many terms as needed in the sequence.

Please note that this recursive relation assumes that the sequence starts with an even number divisible by 37 (in this case, 74). If you need a different starting point, you can adjust the initial term accordingly.

I hope this helps! Let me know if you have any further questions.