Question

Решить методом подстановки систему 4x-y=0 x+y=10

Answer 1

Х=10-у

4(10-у)-у=0

40-4у-у=0

-5у=-40

у=8

х=10-8
х=2

Answer 2

Solving the System of Equations Using the Substitution Method

To solve the system of equations using the substitution method, we will solve one equation for one variable and substitute that expression into the other equation. Let's solve the system of equations:

Equation 1: 4x - y = 0 Equation 2: x + y = 10

We can solve Equation 2 for x and substitute it into Equation 1:

From Equation 2, we have x = 10 - y.

Substituting this value of x into Equation 1, we get:

4(10 - y) - y = 0

Simplifying the equation, we have:

40 - 4y - y = 0 40 - 5y = 0

Now, let's solve this equation for y:

40 - 5y = 0 -5y = -40 y = -40 / -5 y = 8

Substituting the value of y back into Equation 2, we can find the value of x:

x + 8 = 10 x = 10 - 8 x = 2

Therefore, the solution to the system of equations is x = 2 and y = 8.

Note: The solution to the system of equations is x = 2 and y = 8.