Question

X^3-2x^2-2x+1=0ПОМОГИТЕ СРОЧНО РЕШИТЬ ЭТО​

Answer 1

Смотри..........................

Answer 2

Ответ:

Х= - 1

Х1=(3+корень5)/2

Х2=(3-корень5)/2

Объяснение:

Х^3-2х^2-2х+1=0

(Х^3+1)-(2х^2+2х)=0

(x+1)(x^2-x+1)-2x(x+1)=0

(x+1)(x^2-x+1-2x)=0

(x+1)(x^2-3x+1)=0

x+1=0 и x^2-3x+1=0

x= - 1 D=b^2 - 4ac=9-4×1×1=5

X1=(3+корень5)/2

Х2=(3-корень5) /2

Answer 3

Equation Solution for x^3-2x^2-2x+1=0

To solve the equation x^3-2x^2-2x+1=0, we can use various methods such as factoring, the rational root theorem, or numerical methods. Let's explore the solution step by step.

1. Factoring the Equation: - Factoring the equation may help us find its roots. However, factoring a cubic equation can be complex and may not always be feasible.

2. Rational Root Theorem: - The rational root theorem states that any rational root of the equation must be a factor of the constant term (in this case, 1) divided by a factor of the leading coefficient (in this case, 1). This can help us identify potential rational roots to test.

3. Numerical Methods: - If factoring and the rational root theorem do not yield solutions, numerical methods such as the Newton-Raphson method or the bisection method can be used to approximate the roots.

Let's proceed with the rational root theorem to identify potential rational roots for the equation.

Rational Root Theorem: The rational root theorem states that any rational root of the equation must be a factor of the constant term (in this case, 1) divided by a factor of the leading coefficient (in this case, 1). This can help us identify potential rational roots to test.

Using the rational root theorem, the potential rational roots of the equation are the factors of 1, which are ±1. We can test these potential roots to see if they satisfy the equation.

After identifying the potential rational roots, we can use numerical methods if necessary to approximate any remaining roots.

Please let me know if you would like to explore any specific method further or if you have any other questions related to this equation!