Question

Пассажирский поезд был задержан в пути на 16 мин и на гнал опоздание на перегоне в 80км идя со скоростью,на 10км/ч большей,чем полагалась по расписанию. Какова была скорость поезда по расписанию?

Answer 1

Поезд ехал со скоростью Х км/ч
на участке 80 км ехал со скоростью Х+10 км/ч
80 км проехал за 16 мин или 0,26 часа
скорость (Х+10) = расстояние / время 80 / 0,26=308 км/ч
тогда скорость Х 308-10=298 км\ч

Ответ:298

Answer 2

Calculation of the Train's Scheduled Speed

To determine the scheduled speed of the train, we can use the information provided. The train was delayed by 16 minutes and traveled 80 km at a speed that was 10 km/h faster than the scheduled speed.

Let's assume the scheduled speed of the train is represented by x km/h.

According to the given information, the train traveled 80 km at a speed that was 10 km/h faster than the scheduled speed. This can be represented by the equation:

80 = (x + 10) * (16/60)

Simplifying the equation, we have:

80 = (x + 10) * (4/15)

To solve for x, we can cross-multiply:

80 * 15 = (x + 10) * 4

1200 = 4x + 40

Subtracting 40 from both sides:

1160 = 4x

Dividing both sides by 4:

x = 290

Therefore, the scheduled speed of the train was 290 km/h.

Conclusion

The scheduled speed of the train was 290 km/h.