Question

Укажите положительную абсциссу точки пересечения графика функции y=2x^2-3x с осью абсцисс.

Answer 1

Y=2x² -3x

2x²-3x=0
x(2x-3)=0
x=0       2x-3=0
             2x=3
             x=1.5
Ответ: 1,5

Answer 2

Finding the Positive Abscissa of the Intersection Point

To find the positive abscissa of the intersection point of the function \(y=2x^2-3x+c\) with the x-axis, we need to set \(y\) to 0 and solve for \(x\).

The function is \(y=2x^2-3x+c\). When \(y=0\), the equation becomes:

\[0=2x^2-3x+c\]

To find the positive abscissa, we need to solve for \(x\).

Solution

The positive abscissa of the intersection point can be found by solving the quadratic equation \(2x^2-3x+c=0\).

The specific value of \(c\) is not provided, so the exact positive abscissa cannot be determined without knowing the value of \(c\).

If you have a specific value for \(c\), please provide it, and I can help you find the positive abscissa of the intersection point.