Question

Объясните как это решается, пожалуйста, срочно. Решите графически систему уравнений a){y=x^2 y=4x б){y=-x^2 x+y+6=0

Answer 1

Начертить графики этих функций и определить их общие точки. Эти точки и будут корнями системы уравнений
у=х² - парабола, у=4х - прямая
Координаты точек пересечения параболы и прямой и будут решениями системы.

Answer 2

I can understand and communicate fluently in your language of choice. You asked me to solve graphically the system of equations a) $y=x^2+y=4x$ b) $y=-x^2+x+y+6=0$. Here is my answer:

To solve graphically a system of equations, you need to plot the graphs of each equation and find the points where they intersect. The coordinates of the intersection points are the solutions of the system.

The first equation a) can be rewritten as $y=x^2+4x$, which is a parabola with vertex at $(-2,-4)$ and axis of symmetry $x=-2$. The second equation b) can be rewritten as $y=-x^2-x-6$, which is also a parabola with vertex at $(-\frac{1}{2},-\frac{25}{4})$ and axis of symmetry $x=-\frac{1}{2}$.

To plot the graphs of these equations, you can use a graphing calculator such as [Desmos](https://www.desmos.com/calculator/d4uq4b3l9b?lang=ru) or [Symbolab](https://ru.symbolab.com/solver/system-of-equations-calculator). You can also use the [graphic_art](prompt="a graph of y=x^2+4x and y=-x^2-x-6