Question

Пж срочно x^4+9x^2-10=o

Answer 1

Решение смотри на фотографии

Answer 2

To solve the quadratic equation x^4 + 9x^2 - 10 = 0, we can use a substitution to simplify it. Let's make a substitution:

Let u = x^2.

Now, the equation becomes: u^2 + 9u - 10 = 0.

Now we have a simple quadratic equation. To solve for u, we can factor it or use the quadratic formula:

u^2 + 9u - 10 = 0

(u + 10)(u - 1) = 0

Now, set each factor equal to zero and solve for u:

1. u + 10 = 0 u = -10

2. u - 1 = 0 u = 1

Now that we have the values for u, we can substitute back into the original substitution:

1. u = x^2 x^2 = -10

Taking the square root of both sides, remember to consider both the positive and negative square roots:

x = ±√(-10)

2. u = x^2 x^2 = 1

Taking the square root of both sides:

x = ±√(1)

So the solutions to the original equation are:

x = √(-10) or x = -√(-10)

x = √(1) or x = -√(1)

However, the square root of a negative number (√(-10)) is a complex number, and the square root of a positive number (√(1)) is ±1. Therefore, the real solutions for the original equation are:

x = 1 or x = -1.