Question

Help plz! lg(3x-1)=lg(5x+25)

Answer 1

ОДЗ:

3x - 1 > 0       ⇒   x>1/3

5x + 25 > 0   ⇒   x>-5

x ∈ (1/3;  +∞)

Составим уравнение:

3x - 1 = 5x + 25

5x -3x = -1 - 25

2x = - 26

x = - 13 (не принадлежит ОДЗ)

Ответ: решений нет

Answer 2

Смотри........... ......

Answer 3

To solve the equation lg(3x-1) = lg(5x+25), we'll use some properties of logarithms. The key property we'll use is that if lg(a) = lg(b), then a = b.

So, in this case:

lg(3x-1) = lg(5x+25)

Since the logarithms have the same base, we can remove them by setting the expressions inside the logarithms equal to each other:

3x - 1 = 5x + 25

Now, let's solve for x:

Subtract 3x from both sides:

-1 = 2x + 25

Subtract 25 from both sides:

-26 = 2x

Finally, divide by 2 to solve for x:

x = -26 / 2

x = -13

So, the solution to the equation is x = -13.