Question

4х-3у=2 3х+3У=5 додаванеэ

Answer 1

$+\left \{ {{4x-3y=2} \atop {3x+3y=5}} \right.\\ ------\\7x=7\\\\x=1\\\\3y=5-3x=5-3*1=2\\\\y=\frac{2}{3} \\\\Otvet:\boxed{(1;\frac{2}{3})}$

Answer 2

To solve the system of equations using addition (elimination), you can add the two equations together to eliminate one of the variables and solve for the other.

Given the system of equations:

1. $4x - 3y = 2$
2. $3x + 3y = 5$

Let's add the two equations to eliminate the $y$ variable:

Add equation (1) and equation (2):

$(4x - 3y) + (3x + 3y) = 2 + 5$

Simplify the left side:

$4x - 3y + 3x + 3y = 7x$

$7x = 7$

Now, divide both sides by 7:

$x = 1$

Now that you have the value of $x$, you can substitute it back into either of the original equations to solve for $y$. Let's use equation (1):

$4x - 3y = 2$ $4(1) - 3y = 2$ $4 - 3y = 2$

Subtract 4 from both sides:

$-3y = -2$

Divide by -3:

$y = \frac{2}{3}$

So, the solution to the system of equations is $x = 1$ and $y = \frac{2}{3}$.