Question

X2+x-42=0 пжжпжпжпжпжпжп​

Answer 1

Ответ:

x³=42+0

x³=42

x=42:3

x=14

Answer 2

To solve the quadratic equation x^2 + x - 42 = 0, you can use the quadratic formula, which is:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 1, b = 1, and c = -42. Plug these values into the formula and solve for x:

x = (-1 ± √(1^2 - 4(1)(-42))) / (2(1))

x = (-1 ± √(1 + 168)) / 2

x = (-1 ± √169) / 2

x = (-1 ± 13) / 2

Now, we have two possible solutions for x:

1. x = (-1 + 13) / 2 = 12 / 2 = 6
2. x = (-1 - 13) / 2 = -14 / 2 = -7

So, the solutions for the equation x^2 + x - 42 = 0 are x = 6 and x = -7.